b^2-3b-4=(b-4)

Solution for b^2-3b-4=(b-4) equation:

Simplifying
b2 + -3b + -4 = (b + -4)

Reorder the terms:
-4 + -3b + b2 = (b + -4)

Reorder the terms:
-4 + -3b + b2 = (-4 + b)

Remove parenthesis around (-4 + b)
-4 + -3b + b2 = -4 + b

Add '4' to each side of the equation.
-4 + -3b + 4 + b2 = -4 + 4 + b

Reorder the terms:
-4 + 4 + -3b + b2 = -4 + 4 + b

Combine like terms: -4 + 4 = 0
0 + -3b + b2 = -4 + 4 + b
-3b + b2 = -4 + 4 + b

Combine like terms: -4 + 4 = 0
-3b + b2 = 0 + b
-3b + b2 = b

Solving
-3b + b2 = b

Solving for variable 'b'.

Reorder the terms:
-3b + -1b + b2 = b + -1b

Combine like terms: -3b + -1b = -4b
-4b + b2 = b + -1b

Combine like terms: b + -1b = 0
-4b + b2 = 0

Factor out the Greatest Common Factor (GCF), 'b'.
b(-4 + b) = 0

Subproblem 1
Set the factor 'b' equal to zero and attempt to solve:

Simplifying
b = 0

Solving
b = 0

Move all terms containing b to the left, all other terms to the right.

Simplifying
b = 0
Subproblem 2
Set the factor '(-4 + b)' equal to zero and attempt to solve:

Simplifying
-4 + b = 0

Solving
-4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + b = 0 + 4
b = 0 + 4

Combine like terms: 0 + 4 = 4
b = 4

Simplifying
b = 4
Solution
b = {0, 4}